x^2-(10x/3)+1=0

Solution for x^2-(10x/3)+1=0 equation:

x^2-(10x/3)+1=0

We add all the numbers together, and all the variables

x^2-(+10x/3)+1=0

We get rid of parentheses

x^2-10x/3+1=0

We multiply all the terms by the denominator


x^2*3-10x+1*3=0

We add all the numbers together, and all the variables

x^2*3-10x+3=0

Wy multiply elements

3x^2-10x+3=0

a = 3; b = -10; c = +3;
Δ = b2-4ac
Δ = -102-4·3·3
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-8}{2*3}=\frac{2}{6}
=1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+8}{2*3}=\frac{18}{6}
=3
$